Revision history for MatheGKL2
Additions:
**f)**
E(t) = (1+t²)/1+sin(2t)
1+sin(2t) ≠ 0 -> sin(2t) ≠ -1-> 2t≠ 3π/2 + 2kπ
-> t≠ 3π/4 + kπ; k Element Z
D = {t Element R I t≠ 3π/4 + kπ; k Element Z}
E(t) = (1+t²)/1+sin(2t)
1+sin(2t) ≠ 0 -> sin(2t) ≠ -1-> 2t≠ 3π/2 + 2kπ
-> t≠ 3π/4 + kπ; k Element Z
D = {t Element R I t≠ 3π/4 + kπ; k Element Z}
Deletions:
Additions:
**e)**
D(x) = √(x-3)/cos(x)
cos(x) ≠ 0 -> x ≠ π/2 + kπ; k Element Z
x-3 ≥ 0 -> x ≥ 3
D = {x Element R I x ≥ 3; x≠ π/2 +kπ; k Element Z}
D(x) = √(x-3)/cos(x)
cos(x) ≠ 0 -> x ≠ π/2 + kπ; k Element Z
x-3 ≥ 0 -> x ≥ 3
D = {x Element R I x ≥ 3; x≠ π/2 +kπ; k Element Z}
Additions:
**b)**
R(x) = ln(x+1)+1/x²
**c)**
C(t) = (1+√(t-1))/(√-2-t)
t-1 ≥ 0 -> t ≥ 1
-2-t > 0 -> t < -2
D = { }
**d)**
F(x, y) = 1/√x + 1/√y + √(x²-y²)
x²-y² ≥ 0 -> IxI ≥ IyI
x > 0
y > 0 -> Beträge nicht nötig
D = {(x;y)I x>0; y>0; x>y}
R(x) = ln(x+1)+1/x²
**c)**
C(t) = (1+√(t-1))/(√-2-t)
t-1 ≥ 0 -> t ≥ 1
-2-t > 0 -> t < -2
D = { }
**d)**
F(x, y) = 1/√x + 1/√y + √(x²-y²)
x²-y² ≥ 0 -> IxI ≥ IyI
x > 0
y > 0 -> Beträge nicht nötig
D = {(x;y)I x>0; y>0; x>y}
Additions:
||**Geben Sie die Definitionsbereiche an:**
**0.2.1.T**
**a)**
T(x) = 1/(x-2)+√x
x-2 ≠ 0 -> x ≠ 2
x ≥ 0
D = {x Element R I x ≥ 0; x ≠ 2}
||
**0.2.1.T**
**a)**
T(x) = 1/(x-2)+√x
x-2 ≠ 0 -> x ≠ 2
x ≥ 0
D = {x Element R I x ≥ 0; x ≠ 2}
||
Deletions:
Additions:
||cell1||
{{image url="terme1.jpg" width="650" class="center"}}
{{image url="terme1.jpg" width="650" class="center"}}
Deletions:
Additions:
===Definitionsbereich mathematischer Terme - Lösungen===
||**{{files download="MatheGKL2.pdf"text="PDF Dokument Lösungen Definitionsbereich Mathematischer Terme"}}**||
||**{{files download="MatheGKL2.pdf"text="PDF Dokument Lösungen Definitionsbereich Mathematischer Terme"}}**||
Deletions:
===Definitionsbereich mathematischer Terme===
||**{{files download="MatheGKL2.pdf"text="PDF Dokument Grundlagen Mathematische Terme"}}**||
